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3x^2-51x=-216
We move all terms to the left:
3x^2-51x-(-216)=0
We add all the numbers together, and all the variables
3x^2-51x+216=0
a = 3; b = -51; c = +216;
Δ = b2-4ac
Δ = -512-4·3·216
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-51)-3}{2*3}=\frac{48}{6} =8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-51)+3}{2*3}=\frac{54}{6} =9 $
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